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503414320201 = 1347823918691
BaseRepresentation
bin1110101001101011101…
…01001110110001001001
31210010101210212011001021
413110311311032301021
531221443031221301
61023133151552441
751241035055552
oct7246565166111
91703353764037
10503414320201
11184551294831
128169452b721
13386196189a0
141a51887b329
15d1657688a1
hex7535d4ec49

503414320201 has 8 divisors (see below), whose sum is σ = 553673361024. Its totient is φ = 454803116880.

The previous prime is 503414320183. The next prime is 503414320219. The reversal of 503414320201 is 102023414305.

It is an interprime number because it is at equal distance from previous prime (503414320183) and next prime (503414320219).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-503414320201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (503414320271) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 411958735 + ... + 411959956.

It is an arithmetic number, because the mean of its divisors is an integer number (69209170128).

Almost surely, 2503414320201 is an apocalyptic number.

It is an amenable number.

503414320201 is a deficient number, since it is larger than the sum of its proper divisors (50259040823).

503414320201 is a wasteful number, since it uses less digits than its factorization.

503414320201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 823918751.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 503414320201 its reverse (102023414305), we get a palindrome (605437734506).

The spelling of 503414320201 in words is "five hundred three billion, four hundred fourteen million, three hundred twenty thousand, two hundred one".

Divisors: 1 13 47 611 823918691 10710942983 38724178477 503414320201