Base | Representation |
---|---|
bin | 100100101000010000000… |
… | …0110000010000010100011 |
3 | 122211021020211221121010111 |
4 | 1021100200012002002203 |
5 | 1124440110432414133 |
6 | 14412410433112151 |
7 | 1026466110001555 |
oct | 111204006020243 |
9 | 18737224847114 |
10 | 5034240123043 |
11 | 167101134180a |
12 | 6938049b8657 |
13 | 2a695aa428c1 |
14 | 135930dad4d5 |
15 | 8ae437031cd |
hex | 494201820a3 |
5034240123043 has 4 divisors (see below), whose sum is σ = 5035096437840. Its totient is φ = 5033383808248.
The previous prime is 5034240123041. The next prime is 5034240123089. The reversal of 5034240123043 is 3403210424305.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5034240123043 - 21 = 5034240123041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5034240122996 and 5034240123014.
It is not an unprimeable number, because it can be changed into a prime (5034240123041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 428148580 + ... + 428160337.
It is an arithmetic number, because the mean of its divisors is an integer number (1258774109460).
Almost surely, 25034240123043 is an apocalyptic number.
5034240123043 is a deficient number, since it is larger than the sum of its proper divisors (856314797).
5034240123043 is an equidigital number, since it uses as much as digits as its factorization.
5034240123043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 856314796.
The product of its (nonzero) digits is 34560, while the sum is 31.
Adding to 5034240123043 its reverse (3403210424305), we get a palindrome (8437450547348).
The spelling of 5034240123043 in words is "five trillion, thirty-four billion, two hundred forty million, one hundred twenty-three thousand, forty-three".
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