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5034240125041 is a prime number
BaseRepresentation
bin100100101000010000000…
…0110000010100001110001
3122211021020211221200212111
41021100200012002201301
51124440110433000131
614412410433125321
71026466110010441
oct111204006024161
918737224850774
105034240125041
111671011343266
126938049b9841
132a695aa4379a
14135930db0121
158ae43703ab1
hex49420182871

5034240125041 has 2 divisors, whose sum is σ = 5034240125042. Its totient is φ = 5034240125040.

The previous prime is 5034240125027. The next prime is 5034240125063. The reversal of 5034240125041 is 1405210424305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3609848001600 + 1424392123441 = 1899960^2 + 1193479^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034240125041 - 25 = 5034240125009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5034240124994 and 5034240125012.

It is not a weakly prime, because it can be changed into another prime (5034240125441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517120062520 + 2517120062521.

It is an arithmetic number, because the mean of its divisors is an integer number (2517120062521).

Almost surely, 25034240125041 is an apocalyptic number.

It is an amenable number.

5034240125041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034240125041 is an equidigital number, since it uses as much as digits as its factorization.

5034240125041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 5034240125041 its reverse (1405210424305), we get a palindrome (6439450549346).

The spelling of 5034240125041 in words is "five trillion, thirty-four billion, two hundred forty million, one hundred twenty-five thousand, forty-one".