Base | Representation |
---|---|
bin | 100100101000010000000… |
… | …0111001010111000110111 |
3 | 122211021020212111202102220 |
4 | 1021100200013022320313 |
5 | 1124440111021441211 |
6 | 14412410443333423 |
7 | 1026466112353524 |
oct | 111204007127067 |
9 | 18737225452386 |
10 | 5034240421431 |
11 | 1671011525a11 |
12 | 693804b21273 |
13 | 2a695ab18670 |
14 | 13593104a14b |
15 | 8ae43761806 |
hex | 494201cae37 |
5034240421431 has 16 divisors (see below), whose sum is σ = 7241868031104. Its totient is φ = 3092330483424.
The previous prime is 5034240421423. The next prime is 5034240421489. The reversal of 5034240421431 is 1341240424305.
It is not a de Polignac number, because 5034240421431 - 23 = 5034240421423 is a prime.
It is a super-2 number, since 2×50342404214312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5034240421392 and 5034240421401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5034240421411) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 117970521 + ... + 118013186.
It is an arithmetic number, because the mean of its divisors is an integer number (452616751944).
Almost surely, 25034240421431 is an apocalyptic number.
5034240421431 is a deficient number, since it is larger than the sum of its proper divisors (2207627609673).
5034240421431 is a wasteful number, since it uses less digits than its factorization.
5034240421431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235984270.
The product of its (nonzero) digits is 46080, while the sum is 33.
Adding to 5034240421431 its reverse (1341240424305), we get a palindrome (6375480845736).
The spelling of 5034240421431 in words is "five trillion, thirty-four billion, two hundred forty million, four hundred twenty-one thousand, four hundred thirty-one".
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