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503426536241 is a prime number
BaseRepresentation
bin1110101001101101000…
…11110101001100110001
31210010102122211210022012
413110312203311030301
531222004143124431
61023134305452305
751241243645046
oct7246643651461
91703378753265
10503426536241
11184558178932
1281698641095
133861c005105
141a51a33b1cd
15d16687d22b
hex75368f5331

503426536241 has 2 divisors, whose sum is σ = 503426536242. Its totient is φ = 503426536240.

The previous prime is 503426536231. The next prime is 503426536243. The reversal of 503426536241 is 142635624305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 497906640625 + 5519895616 = 705625^2 + 74296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-503426536241 is a prime.

It is a super-2 number, since 2×5034265362412 (a number of 24 digits) contains 22 as substring.

Together with 503426536243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (503426536243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251713268120 + 251713268121.

It is an arithmetic number, because the mean of its divisors is an integer number (251713268121).

Almost surely, 2503426536241 is an apocalyptic number.

It is an amenable number.

503426536241 is a deficient number, since it is larger than the sum of its proper divisors (1).

503426536241 is an equidigital number, since it uses as much as digits as its factorization.

503426536241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 41.

The spelling of 503426536241 in words is "five hundred three billion, four hundred twenty-six million, five hundred thirty-six thousand, two hundred forty-one".