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50342999981 is a prime number
BaseRepresentation
bin101110111000101011…
…010011011110101101
311210221111020101010212
4232320223103132231
51311100301444411
635043253112205
73431355303461
oct567053233655
9153844211125
1050342999981
111a39434700a
12990b928665
134993b449b1
1426180d84a1
151499a4968b
hexbb8ad37ad

50342999981 has 2 divisors, whose sum is σ = 50342999982. Its totient is φ = 50342999980.

The previous prime is 50342999957. The next prime is 50343000011. The reversal of 50342999981 is 18999924305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29877122500 + 20465877481 = 172850^2 + 143059^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50342999981 is a prime.

It is a super-2 number, since 2×503429999812 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 50342999981.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50342999911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25171499990 + 25171499991.

It is an arithmetic number, because the mean of its divisors is an integer number (25171499991).

Almost surely, 250342999981 is an apocalyptic number.

It is an amenable number.

50342999981 is a deficient number, since it is larger than the sum of its proper divisors (1).

50342999981 is an equidigital number, since it uses as much as digits as its factorization.

50342999981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6298560, while the sum is 59.

The spelling of 50342999981 in words is "fifty billion, three hundred forty-two million, nine hundred ninety-nine thousand, nine hundred eighty-one".