Base | Representation |
---|---|
bin | 100100101000010011001… |
… | …0110010100000000011011 |
3 | 122211021112011101122122221 |
4 | 1021100212112110000123 |
5 | 1124440314313213420 |
6 | 14412425102124511 |
7 | 1026501522622450 |
oct | 111204626240033 |
9 | 18737464348587 |
10 | 5034345054235 |
11 | 16710655a1102 |
12 | 693833b80737 |
13 | 2a69766c1a73 |
14 | 135940cc5827 |
15 | 8ae4ca2dcaa |
hex | 4942659401b |
5034345054235 has 8 divisors (see below), whose sum is σ = 6904244645856. Its totient is φ = 3452122322880.
The previous prime is 5034345054229. The next prime is 5034345054241. The reversal of 5034345054235 is 5324505434305.
It is an interprime number because it is at equal distance from previous prime (5034345054229) and next prime (5034345054241).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5034345054235 - 25 = 5034345054203 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5034345054191 and 5034345054200.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71919215026 + ... + 71919215095.
It is an arithmetic number, because the mean of its divisors is an integer number (863030580732).
Almost surely, 25034345054235 is an apocalyptic number.
5034345054235 is a deficient number, since it is larger than the sum of its proper divisors (1869899591621).
5034345054235 is a wasteful number, since it uses less digits than its factorization.
5034345054235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143838430133.
The product of its (nonzero) digits is 2160000, while the sum is 43.
The spelling of 5034345054235 in words is "five trillion, thirty-four billion, three hundred forty-five million, fifty-four thousand, two hundred thirty-five".
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