Base | Representation |
---|---|
bin | 101110111000101111… |
… | …100000111000010001 |
3 | 11210221120022102210202 |
4 | 232320233200320101 |
5 | 1311101042302231 |
6 | 35043332504545 |
7 | 3431400550532 |
oct | 567057407021 |
9 | 153846272722 |
10 | 50344103441 |
11 | 1a394a30065 |
12 | 991017b155 |
13 | 4994140028 |
14 | 2618304689 |
15 | 1499bb65cb |
hex | bb8be0e11 |
50344103441 has 2 divisors, whose sum is σ = 50344103442. Its totient is φ = 50344103440.
The previous prime is 50344103437. The next prime is 50344103471. The reversal of 50344103441 is 14430144305.
It is a happy number.
50344103441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50301069841 + 43033600 = 224279^2 + 6560^2 .
It is a cyclic number.
It is not a de Polignac number, because 50344103441 - 22 = 50344103437 is a prime.
It is not a weakly prime, because it can be changed into another prime (50344103471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25172051720 + 25172051721.
It is an arithmetic number, because the mean of its divisors is an integer number (25172051721).
Almost surely, 250344103441 is an apocalyptic number.
It is an amenable number.
50344103441 is a deficient number, since it is larger than the sum of its proper divisors (1).
50344103441 is an equidigital number, since it uses as much as digits as its factorization.
50344103441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 50344103441 its reverse (14430144305), we get a palindrome (64774247746).
The spelling of 50344103441 in words is "fifty billion, three hundred forty-four million, one hundred three thousand, four hundred forty-one".
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