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5034412022161 is a prime number
BaseRepresentation
bin100100101000010101001…
…0101110001100110010001
3122211021200211101222101111
41021100222111301212101
51124440433434202121
614412435453333321
71026503265060304
oct111205225614621
918737624358344
105034412022161
11167109a3810a5
12693852497241
132a698753b462
14135949b58b3b
158ae5385b2e1
hex4942a571991

5034412022161 has 2 divisors, whose sum is σ = 5034412022162. Its totient is φ = 5034412022160.

The previous prime is 5034412022149. The next prime is 5034412022363. The reversal of 5034412022161 is 1612202144305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3157128402561 + 1877283619600 = 1776831^2 + 1370140^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5034412022161 is a prime.

It is not a weakly prime, because it can be changed into another prime (5034412022131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517206011080 + 2517206011081.

It is an arithmetic number, because the mean of its divisors is an integer number (2517206011081).

Almost surely, 25034412022161 is an apocalyptic number.

It is an amenable number.

5034412022161 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034412022161 is an equidigital number, since it uses as much as digits as its factorization.

5034412022161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 5034412022161 its reverse (1612202144305), we get a palindrome (6646614166466).

The spelling of 5034412022161 in words is "five trillion, thirty-four billion, four hundred twelve million, twenty-two thousand, one hundred sixty-one".