Base | Representation |
---|---|
bin | 100100101000010101001… |
… | …0101110001100101110011 |
3 | 122211021200211101222100101 |
4 | 1021100222111301211303 |
5 | 1124440433434202011 |
6 | 14412435453333231 |
7 | 1026503265060232 |
oct | 111205225614563 |
9 | 18737624358311 |
10 | 5034412022131 |
11 | 167109a381078 |
12 | 693852497217 |
13 | 2a698753b43b |
14 | 135949b58b19 |
15 | 8ae5385b2c1 |
hex | 4942a571973 |
5034412022131 has 2 divisors, whose sum is σ = 5034412022132. Its totient is φ = 5034412022130.
The previous prime is 5034412022089. The next prime is 5034412022149. The reversal of 5034412022131 is 1312202144305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5034412022131 - 211 = 5034412020083 is a prime.
It is a super-2 number, since 2×50344120221312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5034412022131.
It is not a weakly prime, because it can be changed into another prime (5034412022161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517206011065 + 2517206011066.
It is an arithmetic number, because the mean of its divisors is an integer number (2517206011066).
Almost surely, 25034412022131 is an apocalyptic number.
5034412022131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034412022131 is an equidigital number, since it uses as much as digits as its factorization.
5034412022131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 5034412022131 its reverse (1312202144305), we get a palindrome (6346614166436).
The spelling of 5034412022131 in words is "five trillion, thirty-four billion, four hundred twelve million, twenty-two thousand, one hundred thirty-one".
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