Base | Representation |
---|---|
bin | 100100101000110000000… |
… | …0100110011011111011011 |
3 | 122211101000122202222200001 |
4 | 1021101200010303133123 |
5 | 1124444310231340011 |
6 | 14413105140153431 |
7 | 1026534522632314 |
oct | 111214004633733 |
9 | 18741018688601 |
10 | 5035313543131 |
11 | 1671512252153 |
12 | 693a64398877 |
13 | 2a6a9c248211 |
14 | 1359d378d60b |
15 | 8aea7a887c1 |
hex | 494601337db |
5035313543131 has 4 divisors (see below), whose sum is σ = 5043804797592. Its totient is φ = 5026822288672.
The previous prime is 5035313543107. The next prime is 5035313543159. The reversal of 5035313543131 is 1313453135305.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5035313543131 is a prime.
It is a super-2 number, since 2×50353135431312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5035313543191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4245626341 + ... + 4245627526.
It is an arithmetic number, because the mean of its divisors is an integer number (1260951199398).
Almost surely, 25035313543131 is an apocalyptic number.
5035313543131 is a deficient number, since it is larger than the sum of its proper divisors (8491254461).
5035313543131 is an equidigital number, since it uses as much as digits as its factorization.
5035313543131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8491254460.
The product of its (nonzero) digits is 121500, while the sum is 37.
Adding to 5035313543131 its reverse (1313453135305), we get a palindrome (6348766678436).
The spelling of 5035313543131 in words is "five trillion, thirty-five billion, three hundred thirteen million, five hundred forty-three thousand, one hundred thirty-one".
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