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5035500432001 = 13387346187077
BaseRepresentation
bin100100101000110101100…
…1101101110101010000001
3122211101111200102221000001
41021101223031232222001
51130000201102311001
614413135454000001
71026542252311654
oct111215315565201
918741450387001
105035500432001
1116715a879a566
12693ab6aa6001
132a6acbb91850
14135a1051b89b
158aeb91a3001
hex4946b36ea81

5035500432001 has 4 divisors (see below), whose sum is σ = 5422846619092. Its totient is φ = 4648154244912.

The previous prime is 5035500431807. The next prime is 5035500432059. The reversal of 5035500432001 is 1002340055305.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1194214025601 + 3841286406400 = 1092801^2 + 1959920^2 .

It is a cyclic number.

It is not a de Polignac number, because 5035500432001 - 213 = 5035500423809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5035500432301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193673093526 + ... + 193673093551.

It is an arithmetic number, because the mean of its divisors is an integer number (1355711654773).

Almost surely, 25035500432001 is an apocalyptic number.

It is an amenable number.

5035500432001 is a deficient number, since it is larger than the sum of its proper divisors (387346187091).

5035500432001 is a wasteful number, since it uses less digits than its factorization.

5035500432001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 387346187090.

The product of its (nonzero) digits is 9000, while the sum is 28.

Adding to 5035500432001 its reverse (1002340055305), we get a palindrome (6037840487306).

The spelling of 5035500432001 in words is "five trillion, thirty-five billion, five hundred million, four hundred thirty-two thousand, one".

Divisors: 1 13 387346187077 5035500432001