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5038256031 = 31679418677
BaseRepresentation
bin1001011000100110…
…11010111110011111
3111000010100220222020
410230103122332133
540304243143111
62151535151223
7235565320044
oct45423327637
914003326866
105038256031
112155a67366
12b87375513
13623a646b3
1435b1bd1cb
151e74b1906
hex12c4daf9f

5038256031 has 4 divisors (see below), whose sum is σ = 6717674712. Its totient is φ = 3358837352.

The previous prime is 5038255987. The next prime is 5038256033. The reversal of 5038256031 is 1306528305.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5038256031 - 27 = 5038255903 is a prime.

It is a super-3 number, since 3×50382560313 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 5038255983 and 5038256001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5038256033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 839709336 + ... + 839709341.

It is an arithmetic number, because the mean of its divisors is an integer number (1679418678).

Almost surely, 25038256031 is an apocalyptic number.

5038256031 is a deficient number, since it is larger than the sum of its proper divisors (1679418681).

5038256031 is a wasteful number, since it uses less digits than its factorization.

5038256031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1679418680.

The product of its (nonzero) digits is 21600, while the sum is 33.

The square root of 5038256031 is about 70980.6736443097. The cubic root of 5038256031 is about 1714.3259972786.

The spelling of 5038256031 in words is "five billion, thirty-eight million, two hundred fifty-six thousand, thirty-one".

Divisors: 1 3 1679418677 5038256031