Base | Representation |
---|---|
bin | 101110111011101101… |
… | …010010110100001101 |
3 | 11211002000220222122022 |
4 | 232323231102310031 |
5 | 1311201311300242 |
6 | 35052311055525 |
7 | 3432543453542 |
oct | 567355226415 |
9 | 154060828568 |
10 | 50393853197 |
11 | 1a41001a866 |
12 | 99249715a5 |
13 | 49a153b55c |
14 | 2620b74bc9 |
15 | 149e2420d2 |
hex | bbbb52d0d |
50393853197 has 4 divisors (see below), whose sum is σ = 53046161280. Its totient is φ = 47741545116.
The previous prime is 50393853193. The next prime is 50393853227. The reversal of 50393853197 is 79135839305.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50393853197 - 22 = 50393853193 is a prime.
It is a super-5 number, since 5×503938531975 (a number of 55 digits) contains 55555 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50393853193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1326154013 + ... + 1326154050.
It is an arithmetic number, because the mean of its divisors is an integer number (13261540320).
Almost surely, 250393853197 is an apocalyptic number.
It is an amenable number.
50393853197 is a deficient number, since it is larger than the sum of its proper divisors (2652308083).
50393853197 is a wasteful number, since it uses less digits than its factorization.
50393853197 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2652308082.
The product of its (nonzero) digits is 3061800, while the sum is 53.
The spelling of 50393853197 in words is "fifty billion, three hundred ninety-three million, eight hundred fifty-three thousand, one hundred ninety-seven".
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