50401331 has 2 divisors, whose sum is σ = 50401332. Its totient is φ = 50401330.

The previous prime is 50401313. The next prime is 50401367. The reversal of 50401331 is 13310405.

Together with previous prime (50401313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50401331 - 2¹⁰ = 50400307 is a prime.

It is a super-2 number, since 2×50401331² = 5080588333143122, which contains 22 as substring.

It is equal to p_3023720 and since 50401331 and 3023720 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (50401231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25200665 + 25200666.

It is an arithmetic number, because the mean of its divisors is an integer number (25200666).

Almost surely, 2^50401331 is an apocalyptic number.

50401331 is a deficient number, since it is larger than the sum of its proper divisors (1).

50401331 is an equidigital number, since it uses as much as digits as its factorization.

50401331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 50401331 is about 7099.3894807934. The cubic root of 50401331 is about 369.3862017058.

Adding to 50401331 its reverse (13310405), we get a palindrome (63711736).

The spelling of 50401331 in words is "fifty million, four hundred one thousand, three hundred thirty-one".