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5040287547899 is a prime number
BaseRepresentation
bin100100101011000100010…
…0011001000000111111011
3122211211212022020121110212
41021112020203020013323
51130040002103013044
614415250502301335
71030102011161042
oct111261043100773
918754768217425
105040287547899
111673634a1459a
12694a1212784b
132a73b28a48c6
14135d46205559
158b1995a7a9e
hex495888c81fb

5040287547899 has 2 divisors, whose sum is σ = 5040287547900. Its totient is φ = 5040287547898.

The previous prime is 5040287547881. The next prime is 5040287547901. The reversal of 5040287547899 is 9987457820405.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5040287547899 - 236 = 4971568071163 is a prime.

It is a super-3 number, since 3×50402875478993 (a number of 39 digits) contains 333 as substring.

Together with 5040287547901, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5040287547299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520143773949 + 2520143773950.

It is an arithmetic number, because the mean of its divisors is an integer number (2520143773950).

Almost surely, 25040287547899 is an apocalyptic number.

5040287547899 is a deficient number, since it is larger than the sum of its proper divisors (1).

5040287547899 is an equidigital number, since it uses as much as digits as its factorization.

5040287547899 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 203212800, while the sum is 68.

The spelling of 5040287547899 in words is "five trillion, forty billion, two hundred eighty-seven million, five hundred forty-seven thousand, eight hundred ninety-nine".