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50404811250113 = 373374042410077
BaseRepresentation
bin10110111010111110010001…
…10111101001100111000001
320121110122121221221110112022
423131133020313221213001
523101313023140000423
6255111352311211225
713421425132316315
oct1335371067514701
9217418557843468
1050404811250113
1115073618999951
1257a0959376b15
1322181cba74478
14c6386a777b45
155c6228b28dc8
hex2dd7c8de99c1

50404811250113 has 8 divisors (see below), whose sum is σ = 51920715041832. Its totient is φ = 48896992279296.

The previous prime is 50404811250109. The next prime is 50404811250119. The reversal of 50404811250113 is 31105211840405.

It can be written as a sum of positive squares in 4 ways, for example, as 15300051294784 + 35104759955329 = 3911528^2 + 5924927^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 50404811250113 - 22 = 50404811250109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50404811250119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2021192570 + ... + 2021217507.

It is an arithmetic number, because the mean of its divisors is an integer number (6490089380229).

Almost surely, 250404811250113 is an apocalyptic number.

It is an amenable number.

50404811250113 is a deficient number, since it is larger than the sum of its proper divisors (1515903791719).

50404811250113 is a wasteful number, since it uses less digits than its factorization.

50404811250113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4042410451.

The product of its (nonzero) digits is 19200, while the sum is 35.

The spelling of 50404811250113 in words is "fifty trillion, four hundred four billion, eight hundred eleven million, two hundred fifty thousand, one hundred thirteen".

Divisors: 1 37 337 12469 4042410077 149569172849 1362292195949 50404811250113