Base | Representation |
---|---|
bin | 10110111010111110010001… |
… | …10111101001100111000111 |
3 | 20121110122121221221110112112 |
4 | 23131133020313221213013 |
5 | 23101313023140000434 |
6 | 255111352311211235 |
7 | 13421425132316324 |
oct | 1335371067514707 |
9 | 217418557843475 |
10 | 50404811250119 |
11 | 15073618999957 |
12 | 57a0959376b1b |
13 | 22181cba74481 |
14 | c6386a777b4b |
15 | 5c6228b28dce |
hex | 2dd7c8de99c7 |
50404811250119 has 2 divisors, whose sum is σ = 50404811250120. Its totient is φ = 50404811250118.
The previous prime is 50404811250109. The next prime is 50404811250121. The reversal of 50404811250119 is 91105211840405.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50404811250119 is a prime.
It is a super-2 number, since 2×504048112501192 (a number of 28 digits) contains 22 as substring.
Together with 50404811250121, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50404811250109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25202405625059 + 25202405625060.
It is an arithmetic number, because the mean of its divisors is an integer number (25202405625060).
Almost surely, 250404811250119 is an apocalyptic number.
50404811250119 is a deficient number, since it is larger than the sum of its proper divisors (1).
50404811250119 is an equidigital number, since it uses as much as digits as its factorization.
50404811250119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 41.
The spelling of 50404811250119 in words is "fifty trillion, four hundred four billion, eight hundred eleven million, two hundred fifty thousand, one hundred nineteen".
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