5041131131 has 2 divisors, whose sum is σ = 5041131132. Its totient is φ = 5041131130.

The previous prime is 5041131113. The next prime is 5041131133. The reversal of 5041131131 is 1311311405.

Together with previous prime (5041131113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5041131131 is a prime.

It is a super-2 number, since 2×5041131131² = 50826006159874678322, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 5041131133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5041131133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520565565 + 2520565566.

It is an arithmetic number, because the mean of its divisors is an integer number (2520565566).

Almost surely, 2^5041131131 is an apocalyptic number.

5041131131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5041131131 is an equidigital number, since it uses as much as digits as its factorization.

5041131131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 20.

The square root of 5041131131 is about 71000.9234517411. The cubic root of 5041131131 is about 1714.6520308230.

Adding to 5041131131 its reverse (1311311405), we get a palindrome (6352442536).

The spelling of 5041131131 in words is "five billion, forty-one million, one hundred thirty-one thousand, one hundred thirty-one".