50411403613 has 2 divisors, whose sum is σ = 50411403614. Its totient is φ = 50411403612.

The previous prime is 50411403499. The next prime is 50411403617. The reversal of 50411403613 is 31630411405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30463513444 + 19947890169 = 174538^2 + 141237^2 .

It is a cyclic number.

It is not a de Polignac number, because 50411403613 - 2¹³ = 50411395421 is a prime.

It is a super-2 number, since 2×50411403613² (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50411403617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25205701806 + 25205701807.

It is an arithmetic number, because the mean of its divisors is an integer number (25205701807).

Almost surely, 2^50411403613 is an apocalyptic number.

It is an amenable number.

50411403613 is a deficient number, since it is larger than the sum of its proper divisors (1).

50411403613 is an equidigital number, since it uses as much as digits as its factorization.

50411403613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

The spelling of 50411403613 in words is "fifty billion, four hundred eleven million, four hundred three thousand, six hundred thirteen".