Base | Representation |
---|---|
bin | 101110111100110000… |
… | …011100001010100101 |
3 | 11211010021001020222011 |
4 | 232330300130022211 |
5 | 1311220313031031 |
6 | 35054140234221 |
7 | 3433146204265 |
oct | 567460341245 |
9 | 154107036864 |
10 | 50411455141 |
11 | 1a419a52423 |
12 | 992a83b971 |
13 | 49a50922c8 |
14 | 26232377a5 |
15 | 14a0a6c6b1 |
hex | bbcc1c2a5 |
50411455141 has 2 divisors, whose sum is σ = 50411455142. Its totient is φ = 50411455140.
The previous prime is 50411455111. The next prime is 50411455181. The reversal of 50411455141 is 14155411405.
50411455141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49928114916 + 483340225 = 223446^2 + 21985^2 .
It is a cyclic number.
It is not a de Polignac number, because 50411455141 - 217 = 50411324069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50411455111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25205727570 + 25205727571.
It is an arithmetic number, because the mean of its divisors is an integer number (25205727571).
Almost surely, 250411455141 is an apocalyptic number.
It is an amenable number.
50411455141 is a deficient number, since it is larger than the sum of its proper divisors (1).
50411455141 is an equidigital number, since it uses as much as digits as its factorization.
50411455141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8000, while the sum is 31.
Adding to 50411455141 its reverse (14155411405), we get a palindrome (64566866546).
The spelling of 50411455141 in words is "fifty billion, four hundred eleven million, four hundred fifty-five thousand, one hundred forty-one".
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