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5041157995793 is a prime number
BaseRepresentation
bin100100101011011110001…
…1011100111110100010001
3122211221002222010221111202
41021112330123213310101
51130043242421331133
614415513115120545
71030132410645023
oct111267433476421
918757088127452
105041157995793
111673a412a1a17
12695015743155
132a74c102212a
14135dc9a6c013
158b1eabe82e8
hex495bc6e7d11

5041157995793 has 2 divisors, whose sum is σ = 5041157995794. Its totient is φ = 5041157995792.

The previous prime is 5041157995733. The next prime is 5041157995813. The reversal of 5041157995793 is 3975997511405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2592283543249 + 2448874452544 = 1610057^2 + 1564888^2 .

It is a cyclic number.

It is not a de Polignac number, because 5041157995793 - 218 = 5041157733649 is a prime.

It is not a weakly prime, because it can be changed into another prime (5041157995723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520578997896 + 2520578997897.

It is an arithmetic number, because the mean of its divisors is an integer number (2520578997897).

Almost surely, 25041157995793 is an apocalyptic number.

It is an amenable number.

5041157995793 is a deficient number, since it is larger than the sum of its proper divisors (1).

5041157995793 is an equidigital number, since it uses as much as digits as its factorization.

5041157995793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 53581500, while the sum is 65.

The spelling of 5041157995793 in words is "five trillion, forty-one billion, one hundred fifty-seven million, nine hundred ninety-five thousand, seven hundred ninety-three".