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5041245312013 is a prime number
BaseRepresentation
bin100100101011100000110…
…1000101101010000001101
3122211221100001110001211211
41021113001220231100031
51130043432244441023
614415525514414421
71030134521062201
oct111270150552015
918757301401754
105041245312013
111673a8660a989
1269503aa31411
132a7506144631
14135dd74bab01
158b2036e4a0d
hex495c1a2d40d

5041245312013 has 2 divisors, whose sum is σ = 5041245312014. Its totient is φ = 5041245312012.

The previous prime is 5041245311959. The next prime is 5041245312041. The reversal of 5041245312013 is 3102135421405.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4872959120484 + 168286191529 = 2207478^2 + 410227^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5041245312013 is a prime.

It is a super-2 number, since 2×50412453120132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5041245312413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2520622656006 + 2520622656007.

It is an arithmetic number, because the mean of its divisors is an integer number (2520622656007).

Almost surely, 25041245312013 is an apocalyptic number.

It is an amenable number.

5041245312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

5041245312013 is an equidigital number, since it uses as much as digits as its factorization.

5041245312013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 5041245312013 in words is "five trillion, forty-one billion, two hundred forty-five million, three hundred twelve thousand, thirteen".