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504213001 is a prime number
BaseRepresentation
bin11110000011011…
…010111000001001
31022010202200012121
4132003122320021
52013034304001
6122011011241
715331511515
oct3603327011
91263680177
10504213001
11239684766
12120a39b21
13805cb8b6
144ad71145
152e3eb6a1
hex1e0dae09

504213001 has 2 divisors, whose sum is σ = 504213002. Its totient is φ = 504213000.

The previous prime is 504212999. The next prime is 504213037. The reversal of 504213001 is 100312405.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 476112400 + 28100601 = 21820^2 + 5301^2 .

It is a cyclic number.

It is not a de Polignac number, because 504213001 - 21 = 504212999 is a prime.

Together with 504212999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (504213041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252106500 + 252106501.

It is an arithmetic number, because the mean of its divisors is an integer number (252106501).

Almost surely, 2504213001 is an apocalyptic number.

It is an amenable number.

504213001 is a deficient number, since it is larger than the sum of its proper divisors (1).

504213001 is an equidigital number, since it uses as much as digits as its factorization.

504213001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 504213001 is about 22454.6877288463. The cubic root of 504213001 is about 795.9235346740.

Adding to 504213001 its reverse (100312405), we get a palindrome (604525406).

The spelling of 504213001 in words is "five hundred four million, two hundred thirteen thousand, one".