Base | Representation |
---|---|
bin | 100100101100010101110… |
… | …1111001110010111101111 |
3 | 122212002221010000011221101 |
4 | 1021120223233032113233 |
5 | 1130111104000433143 |
6 | 14420422304143531 |
7 | 1030226604446665 |
oct | 111305357162757 |
9 | 18762833004841 |
10 | 5043025405423 |
11 | 167480a408465 |
12 | 695457007ba7 |
13 | 2a772ab84945 |
14 | 136125a90c35 |
15 | 8b2a9b19b4d |
hex | 4962bbce5ef |
5043025405423 has 4 divisors (see below), whose sum is σ = 5065241376600. Its totient is φ = 5020809434248.
The previous prime is 5043025405387. The next prime is 5043025405469. The reversal of 5043025405423 is 3245045203405.
5043025405423 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5043025405423 - 229 = 5042488534511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5043025405123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11107985248 + ... + 11107985701.
It is an arithmetic number, because the mean of its divisors is an integer number (1266310344150).
Almost surely, 25043025405423 is an apocalyptic number.
5043025405423 is a deficient number, since it is larger than the sum of its proper divisors (22215971177).
5043025405423 is a wasteful number, since it uses less digits than its factorization.
5043025405423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22215971176.
The product of its (nonzero) digits is 288000, while the sum is 37.
The spelling of 5043025405423 in words is "five trillion, forty-three billion, twenty-five million, four hundred five thousand, four hundred twenty-three".
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