Base | Representation |
---|---|
bin | 100100101100011000110… |
… | …1001010111110000111101 |
3 | 122212010012000112110020111 |
4 | 1021120301221113300331 |
5 | 1130111304340044313 |
6 | 14420440204550021 |
7 | 1030232220153364 |
oct | 111306151276075 |
9 | 18763160473214 |
10 | 5043124534333 |
11 | 1674860364486 |
12 | 695484252311 |
13 | 2a7745581ac2 |
14 | 136134cd67db |
15 | 8b2b369b43d |
hex | 49631a57c3d |
5043124534333 has 2 divisors, whose sum is σ = 5043124534334. Its totient is φ = 5043124534332.
The previous prime is 5043124534309. The next prime is 5043124534361. The reversal of 5043124534333 is 3334354213405.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3057612451609 + 1985512082724 = 1748603^2 + 1409082^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5043124534333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5043124534433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2521562267166 + 2521562267167.
It is an arithmetic number, because the mean of its divisors is an integer number (2521562267167).
Almost surely, 25043124534333 is an apocalyptic number.
It is an amenable number.
5043124534333 is a deficient number, since it is larger than the sum of its proper divisors (1).
5043124534333 is an equidigital number, since it uses as much as digits as its factorization.
5043124534333 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 777600, while the sum is 40.
Adding to 5043124534333 its reverse (3334354213405), we get a palindrome (8377478747738).
The spelling of 5043124534333 in words is "five trillion, forty-three billion, one hundred twenty-four million, five hundred thirty-four thousand, three hundred thirty-three".
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