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50434020281 is a prime number
BaseRepresentation
bin101110111110000110…
…100001001110111001
311211011211111200112002
4232332012201032321
51311242102122111
635100304030345
73433542046001
oct567606411671
9154154450462
1050434020281
111a4307649a7
1299363023b5
1349a9963168
14262622d001
1514a2a2863b
hexbbe1a13b9

50434020281 has 2 divisors, whose sum is σ = 50434020282. Its totient is φ = 50434020280.

The previous prime is 50434020167. The next prime is 50434020331. The reversal of 50434020281 is 18202043405.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44825358400 + 5608661881 = 211720^2 + 74891^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50434020281 is a prime.

It is a super-3 number, since 3×504340202813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (50434040281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25217010140 + 25217010141.

It is an arithmetic number, because the mean of its divisors is an integer number (25217010141).

Almost surely, 250434020281 is an apocalyptic number.

It is an amenable number.

50434020281 is a deficient number, since it is larger than the sum of its proper divisors (1).

50434020281 is an equidigital number, since it uses as much as digits as its factorization.

50434020281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 50434020281 its reverse (18202043405), we get a palindrome (68636063686).

The spelling of 50434020281 in words is "fifty billion, four hundred thirty-four million, twenty thousand, two hundred eighty-one".