Base | Representation |
---|---|
bin | 10110111100000001111011… |
… | …10101110100010100011011 |
3 | 20121121010101022120000012202 |
4 | 23132000331311310110123 |
5 | 23102411420130123311 |
6 | 255140200430000415 |
7 | 13424152211002412 |
oct | 1336007565642433 |
9 | 217533338500182 |
10 | 50441133442331 |
11 | 15087a67915525 |
12 | 57a79b564610b |
13 | 221b769ba32b8 |
14 | c65514700479 |
15 | 5c71527cee3b |
hex | 2de03dd7451b |
50441133442331 has 2 divisors, whose sum is σ = 50441133442332. Its totient is φ = 50441133442330.
The previous prime is 50441133442309. The next prime is 50441133442333. The reversal of 50441133442331 is 13324433114405.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50441133442331 is a prime.
It is a super-2 number, since 2×504411334423312 (a number of 28 digits) contains 22 as substring.
Together with 50441133442333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (50441133442333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25220566721165 + 25220566721166.
It is an arithmetic number, because the mean of its divisors is an integer number (25220566721166).
Almost surely, 250441133442331 is an apocalyptic number.
50441133442331 is a deficient number, since it is larger than the sum of its proper divisors (1).
50441133442331 is an equidigital number, since it uses as much as digits as its factorization.
50441133442331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 50441133442331 its reverse (13324433114405), we get a palindrome (63765566556736).
The spelling of 50441133442331 in words is "fifty trillion, four hundred forty-one billion, one hundred thirty-three million, four hundred forty-two thousand, three hundred thirty-one".
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