Base | Representation |
---|---|
bin | 101110111111010000… |
… | …100011111110000111 |
3 | 11211020012000210212011 |
4 | 232333100203332013 |
5 | 1311312034231101 |
6 | 35102240035051 |
7 | 3434166036355 |
oct | 567720437607 |
9 | 154205023764 |
10 | 50453430151 |
11 | 1a440711913 |
12 | 9940902a87 |
13 | 49b099aaa7 |
14 | 2628a427d5 |
15 | 14a45ae751 |
hex | bbf423f87 |
50453430151 has 2 divisors, whose sum is σ = 50453430152. Its totient is φ = 50453430150.
The previous prime is 50453430143. The next prime is 50453430163. The reversal of 50453430151 is 15103435405.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50453430151 - 23 = 50453430143 is a prime.
It is a super-2 number, since 2×504534301512 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50453430551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25226715075 + 25226715076.
It is an arithmetic number, because the mean of its divisors is an integer number (25226715076).
Almost surely, 250453430151 is an apocalyptic number.
50453430151 is a deficient number, since it is larger than the sum of its proper divisors (1).
50453430151 is an equidigital number, since it uses as much as digits as its factorization.
50453430151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 50453430151 its reverse (15103435405), we get a palindrome (65556865556).
The spelling of 50453430151 in words is "fifty billion, four hundred fifty-three million, four hundred thirty thousand, one hundred fifty-one".
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