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50500504996817 is a prime number
BaseRepresentation
bin10110111101110000100001…
…01010010100101111010001
320121210210122000121110210012
423132320100222110233101
523104400013234344232
6255223340044244305
713431353406615431
oct1336702052245721
9217723560543705
1050500504996817
1115100164586127
1257b7404b40695
13222423c385325
14c683479242c1
155c8979c969b2
hex2dee10a94bd1

50500504996817 has 2 divisors, whose sum is σ = 50500504996818. Its totient is φ = 50500504996816.

The previous prime is 50500504996789. The next prime is 50500504996853. The reversal of 50500504996817 is 71869940500505.

50500504996817 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48548996579521 + 1951508417296 = 6967711^2 + 1396964^2 .

It is a cyclic number.

It is not a de Polignac number, because 50500504996817 - 228 = 50500236561361 is a prime.

It is not a weakly prime, because it can be changed into another prime (50500504996517) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25250252498408 + 25250252498409.

It is an arithmetic number, because the mean of its divisors is an integer number (25250252498409).

Almost surely, 250500504996817 is an apocalyptic number.

It is an amenable number.

50500504996817 is a deficient number, since it is larger than the sum of its proper divisors (1).

50500504996817 is an equidigital number, since it uses as much as digits as its factorization.

50500504996817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608000, while the sum is 59.

The spelling of 50500504996817 in words is "fifty trillion, five hundred billion, five hundred four million, nine hundred ninety-six thousand, eight hundred seventeen".