Base | Representation |
---|---|
bin | 101111000010001001… |
… | …111000110010110011 |
3 | 11211100120110000201222 |
4 | 233002021320302303 |
5 | 1311412003341313 |
6 | 35111133215255 |
7 | 3435326006555 |
oct | 570211706263 |
9 | 154316400658 |
10 | 50502012083 |
11 | 1a466084176 |
12 | 995503152b |
13 | 49baa7a8b3 |
14 | 263128b4d5 |
15 | 14a89a9208 |
hex | bc2278cb3 |
50502012083 has 2 divisors, whose sum is σ = 50502012084. Its totient is φ = 50502012082.
The previous prime is 50502012059. The next prime is 50502012107. The reversal of 50502012083 is 38021020505.
50502012083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (50502012059) and next prime (50502012107).
It is a cyclic number.
It is not a de Polignac number, because 50502012083 - 28 = 50502011827 is a prime.
It is not a weakly prime, because it can be changed into another prime (50502012023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25251006041 + 25251006042.
It is an arithmetic number, because the mean of its divisors is an integer number (25251006042).
Almost surely, 250502012083 is an apocalyptic number.
50502012083 is a deficient number, since it is larger than the sum of its proper divisors (1).
50502012083 is an equidigital number, since it uses as much as digits as its factorization.
50502012083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 50502012083 its reverse (38021020505), we get a palindrome (88523032588).
The spelling of 50502012083 in words is "fifty billion, five hundred two million, twelve thousand, eighty-three".
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