Base | Representation |
---|---|
bin | 100100110000001011101… |
… | …1011101000010111110101 |
3 | 122212220020000102200220101 |
4 | 1021200113123220113311 |
5 | 1130230002303044232 |
6 | 14424305030234101 |
7 | 1030641203113615 |
oct | 111402733502765 |
9 | 18786200380811 |
10 | 5051274659317 |
11 | 1678262949a67 |
12 | 696b797b5931 |
13 | 2a8443c38973 |
14 | 1366a94bca45 |
15 | 8b5dde4d1e7 |
hex | 498176e85f5 |
5051274659317 has 2 divisors, whose sum is σ = 5051274659318. Its totient is φ = 5051274659316.
The previous prime is 5051274659309. The next prime is 5051274659329. The reversal of 5051274659317 is 7139564721505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4615798730481 + 435475928836 = 2148441^2 + 659906^2 .
It is a cyclic number.
It is not a de Polignac number, because 5051274659317 - 23 = 5051274659309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5051274689317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525637329658 + 2525637329659.
It is an arithmetic number, because the mean of its divisors is an integer number (2525637329659).
Almost surely, 25051274659317 is an apocalyptic number.
It is an amenable number.
5051274659317 is a deficient number, since it is larger than the sum of its proper divisors (1).
5051274659317 is an equidigital number, since it uses as much as digits as its factorization.
5051274659317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7938000, while the sum is 55.
The spelling of 5051274659317 in words is "five trillion, fifty-one billion, two hundred seventy-four million, six hundred fifty-nine thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •