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5051355225041 is a prime number
BaseRepresentation
bin100100110000001110000…
…1110111101101111010001
3122212220102122000212022002
41021200130032331233101
51130230133414200131
614424321025123345
71030643201654246
oct111403416755721
918786378025262
105051355225041
1116782a4377204
12696ba0789555
132a84578366a8
141366b60915cd
158b5e60646cb
hex4981c3bdbd1

5051355225041 has 2 divisors, whose sum is σ = 5051355225042. Its totient is φ = 5051355225040.

The previous prime is 5051355225019. The next prime is 5051355225043. The reversal of 5051355225041 is 1405225531505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5051350645441 + 4579600 = 2247521^2 + 2140^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5051355225041 is a prime.

Together with 5051355225043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5051355224986 and 5051355225004.

It is not a weakly prime, because it can be changed into another prime (5051355225043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2525677612520 + 2525677612521.

It is an arithmetic number, because the mean of its divisors is an integer number (2525677612521).

Almost surely, 25051355225041 is an apocalyptic number.

It is an amenable number.

5051355225041 is a deficient number, since it is larger than the sum of its proper divisors (1).

5051355225041 is an equidigital number, since it uses as much as digits as its factorization.

5051355225041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 5051355225041 in words is "five trillion, fifty-one billion, three hundred fifty-five million, two hundred twenty-five thousand, forty-one".