Base | Representation |
---|---|
bin | 101111000011111001… |
… | …101011000100000011 |
3 | 11211102121120211010011 |
4 | 233003321223010003 |
5 | 1311442004102341 |
6 | 35114101245351 |
7 | 3436133045623 |
oct | 570371530403 |
9 | 154377524104 |
10 | 50531315971 |
11 | 1a480679664 |
12 | 9962a03857 |
13 | 49c3b6aa86 |
14 | 2635118883 |
15 | 14ab346b81 |
hex | bc3e6b103 |
50531315971 has 2 divisors, whose sum is σ = 50531315972. Its totient is φ = 50531315970.
The previous prime is 50531315957. The next prime is 50531315999. The reversal of 50531315971 is 17951313505.
It is a happy number.
50531315971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50531315971 - 29 = 50531315459 is a prime.
It is a super-3 number, since 3×505313159713 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50537315971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25265657985 + 25265657986.
It is an arithmetic number, because the mean of its divisors is an integer number (25265657986).
Almost surely, 250531315971 is an apocalyptic number.
50531315971 is a deficient number, since it is larger than the sum of its proper divisors (1).
50531315971 is an equidigital number, since it uses as much as digits as its factorization.
50531315971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70875, while the sum is 40.
It can be divided in two parts, 505313 and 15971, that added together give a square (521284 = 7222).
The spelling of 50531315971 in words is "fifty billion, five hundred thirty-one million, three hundred fifteen thousand, nine hundred seventy-one".
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