Base | Representation |
---|---|
bin | 100100110001000101010… |
… | …0000110111100100000111 |
3 | 122220002012120111002210211 |
4 | 1021202022200313210013 |
5 | 1130242431041141403 |
6 | 14425224401100251 |
7 | 1031040066205522 |
oct | 111421240674407 |
9 | 18802176432724 |
10 | 5053205412103 |
11 | 167906379a122 |
12 | 697418327687 |
13 | 2a8690c49034 |
14 | 13680daadbb9 |
15 | 8b6a36d306d |
hex | 4988a837907 |
5053205412103 has 2 divisors, whose sum is σ = 5053205412104. Its totient is φ = 5053205412102.
The previous prime is 5053205412089. The next prime is 5053205412109. The reversal of 5053205412103 is 3012145023505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5053205412103 - 25 = 5053205412071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5053205412109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526602706051 + 2526602706052.
It is an arithmetic number, because the mean of its divisors is an integer number (2526602706052).
Almost surely, 25053205412103 is an apocalyptic number.
5053205412103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5053205412103 is an equidigital number, since it uses as much as digits as its factorization.
5053205412103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 5053205412103 in words is "five trillion, fifty-three billion, two hundred five million, four hundred twelve thousand, one hundred three".
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