Base | Representation |
---|---|
bin | 100100110001000101010… |
… | …0001010100101100101011 |
3 | 122220002012120201011111112 |
4 | 1021202022201110230223 |
5 | 1130242431104001220 |
6 | 14425224403420535 |
7 | 1031040100213445 |
oct | 111421241245453 |
9 | 18802176634445 |
10 | 5053205531435 |
11 | 1679063870846 |
12 | 69741838474b |
13 | 2a8690c8b449 |
14 | 13680db01495 |
15 | 8b6a37085c5 |
hex | 4988a854b2b |
5053205531435 has 32 divisors (see below), whose sum is σ = 6470707921920. Its totient is φ = 3777459408000.
The previous prime is 5053205531399. The next prime is 5053205531453. The reversal of 5053205531435 is 5341355023505.
It is not a de Polignac number, because 5053205531435 - 214 = 5053205515051 is a prime.
It is a super-2 number, since 2×50532055314352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5053205531392 and 5053205531401.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1522250 + ... + 3524720.
It is an arithmetic number, because the mean of its divisors is an integer number (202209622560).
Almost surely, 25053205531435 is an apocalyptic number.
5053205531435 is a deficient number, since it is larger than the sum of its proper divisors (1417502390485).
5053205531435 is a wasteful number, since it uses less digits than its factorization.
5053205531435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2002859.
The product of its (nonzero) digits is 675000, while the sum is 41.
The spelling of 5053205531435 in words is "five trillion, fifty-three billion, two hundred five million, five hundred thirty-one thousand, four hundred thirty-five".
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