Base | Representation |
---|---|
bin | 100100110001000101011… |
… | …1010100011001000001111 |
3 | 122220002020001011010102122 |
4 | 1021202022322203020033 |
5 | 1130242434302103033 |
6 | 14425225201243155 |
7 | 1031040210344462 |
oct | 111421272431017 |
9 | 18802201133378 |
10 | 5053212144143 |
11 | 1679067577a99 |
12 | 69741a6334bb |
13 | 2a86924652a7 |
14 | 1368109432d9 |
15 | 8b6a40b2a98 |
hex | 4988aea320f |
5053212144143 has 2 divisors, whose sum is σ = 5053212144144. Its totient is φ = 5053212144142.
The previous prime is 5053212144109. The next prime is 5053212144173. The reversal of 5053212144143 is 3414412123505.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5053212144143 - 220 = 5053211095567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5053212144173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526606072071 + 2526606072072.
It is an arithmetic number, because the mean of its divisors is an integer number (2526606072072).
Almost surely, 25053212144143 is an apocalyptic number.
5053212144143 is a deficient number, since it is larger than the sum of its proper divisors (1).
5053212144143 is an equidigital number, since it uses as much as digits as its factorization.
5053212144143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 5053212144143 its reverse (3414412123505), we get a palindrome (8467624267648).
The spelling of 5053212144143 in words is "five trillion, fifty-three billion, two hundred twelve million, one hundred forty-four thousand, one hundred forty-three".
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