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5053252132311 = 31684417377437
BaseRepresentation
bin100100110001000110101…
…0011000101110111010111
3122220002022211101201212220
41021202031103011313113
51130243030021213221
614425233150313423
71031041204263165
oct111421523056727
918802284351786
105053252132311
1116790880aa769
1269742bab8873
132a869a826626
14136815d92235
158b6a78610c6
hex4988d4c5dd7

5053252132311 has 4 divisors (see below), whose sum is σ = 6737669509752. Its totient is φ = 3368834754872.

The previous prime is 5053252132301. The next prime is 5053252132471. The reversal of 5053252132311 is 1132312523505.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5053252132311 - 29 = 5053252131799 is a prime.

It is a super-3 number, since 3×50532521323113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5053252132301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 842208688716 + ... + 842208688721.

It is an arithmetic number, because the mean of its divisors is an integer number (1684417377438).

Almost surely, 25053252132311 is an apocalyptic number.

5053252132311 is a deficient number, since it is larger than the sum of its proper divisors (1684417377441).

5053252132311 is a wasteful number, since it uses less digits than its factorization.

5053252132311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1684417377440.

The product of its (nonzero) digits is 27000, while the sum is 33.

Adding to 5053252132311 its reverse (1132312523505), we get a palindrome (6185564655816).

The spelling of 5053252132311 in words is "five trillion, fifty-three billion, two hundred fifty-two million, one hundred thirty-two thousand, three hundred eleven".

Divisors: 1 3 1684417377437 5053252132311