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5053314513397 is a prime number
BaseRepresentation
bin100100110001001000100…
…0001000011100111110101
3122220002111011210000122111
41021202101001003213311
51130243142003412042
614425243255331021
71031042562435223
oct111422101034765
918802434700574
105053314513397
11167910a337587
12697448980a71
132a86aa728307
1413682038db13
158b6ad084517
hex498910439f5

5053314513397 has 2 divisors, whose sum is σ = 5053314513398. Its totient is φ = 5053314513396.

The previous prime is 5053314513311. The next prime is 5053314513449. The reversal of 5053314513397 is 7933154133505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2959256622001 + 2094057891396 = 1720249^2 + 1447086^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5053314513397 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5053314513397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5053314583397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2526657256698 + 2526657256699.

It is an arithmetic number, because the mean of its divisors is an integer number (2526657256699).

Almost surely, 25053314513397 is an apocalyptic number.

It is an amenable number.

5053314513397 is a deficient number, since it is larger than the sum of its proper divisors (1).

5053314513397 is an equidigital number, since it uses as much as digits as its factorization.

5053314513397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2551500, while the sum is 49.

The spelling of 5053314513397 in words is "five trillion, fifty-three billion, three hundred fourteen million, five hundred thirteen thousand, three hundred ninety-seven".