Base | Representation |
---|---|
bin | 1110101101011011011… |
… | …01001010111110010111 |
3 | 1210022120222012022121221 |
4 | 13112231231022332113 |
5 | 31240102410122211 |
6 | 1024104513551211 |
7 | 51341625432214 |
oct | 7265555127627 |
9 | 1708528168557 |
10 | 505425473431 |
11 | 185393559a3a |
12 | 81b55b75507 |
13 | 3887a199798 |
14 | 1a6699dab0b |
15 | d2320d0c71 |
hex | 75adb4af97 |
505425473431 has 2 divisors, whose sum is σ = 505425473432. Its totient is φ = 505425473430.
The previous prime is 505425473389. The next prime is 505425473489. The reversal of 505425473431 is 134374524505.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-505425473431 is a prime.
It is a super-2 number, since 2×5054254734312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (505425476431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252712736715 + 252712736716.
It is an arithmetic number, because the mean of its divisors is an integer number (252712736716).
Almost surely, 2505425473431 is an apocalyptic number.
505425473431 is a deficient number, since it is larger than the sum of its proper divisors (1).
505425473431 is an equidigital number, since it uses as much as digits as its factorization.
505425473431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008000, while the sum is 43.
Adding to 505425473431 its reverse (134374524505), we get a palindrome (639799997936).
The spelling of 505425473431 in words is "five hundred five billion, four hundred twenty-five million, four hundred seventy-three thousand, four hundred thirty-one".
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