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50543143111 = 52197011791
BaseRepresentation
bin101111000100100110…
…110010100011000111
311211110102211200220101
4233010212302203013
51312003021034421
635115202544531
73436335425236
oct570446624307
9154412750811
1050543143111
111a48731755a
129966968147
1349c644c196
142636916b1d
1514ac3d1191
hexbc49b28c7

50543143111 has 4 divisors (see below), whose sum is σ = 50640155424. Its totient is φ = 50446130800.

The previous prime is 50543143109. The next prime is 50543143117. The reversal of 50543143111 is 11134134505.

50543143111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 50543143111 - 21 = 50543143109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 50543143111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (50543143117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48505375 + ... + 48506416.

It is an arithmetic number, because the mean of its divisors is an integer number (12660038856).

Almost surely, 250543143111 is an apocalyptic number.

50543143111 is a deficient number, since it is larger than the sum of its proper divisors (97012313).

50543143111 is an equidigital number, since it uses as much as digits as its factorization.

50543143111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97012312.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 50543143111 its reverse (11134134505), we get a palindrome (61677277616).

The spelling of 50543143111 in words is "fifty billion, five hundred forty-three million, one hundred forty-three thousand, one hundred eleven".

Divisors: 1 521 97011791 50543143111