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50543421446333 is a prime number
BaseRepresentation
bin10110111111000000011101…
…01011100101100010111101
320121221220101221110222220102
423133200032223211202331
523111100411342240313
6255255154404530445
713434433046460464
oct1337401653454275
9217856357428812
1050543421446333
1115117387818922
1258037a16b0a25
1322282bb71795a
14c6a4595899db
155c9b3c81ba58
hex2df80eae58bd

50543421446333 has 2 divisors, whose sum is σ = 50543421446334. Its totient is φ = 50543421446332.

The previous prime is 50543421446327. The next prime is 50543421446341. The reversal of 50543421446333 is 33364412434505.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40258174774489 + 10285246671844 = 6344933^2 + 3207062^2 .

It is a cyclic number.

It is not a de Polignac number, because 50543421446333 - 228 = 50543153010877 is a prime.

It is a super-3 number, since 3×505434214463333 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50543421446233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25271710723166 + 25271710723167.

It is an arithmetic number, because the mean of its divisors is an integer number (25271710723167).

Almost surely, 250543421446333 is an apocalyptic number.

It is an amenable number.

50543421446333 is a deficient number, since it is larger than the sum of its proper divisors (1).

50543421446333 is an equidigital number, since it uses as much as digits as its factorization.

50543421446333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6220800, while the sum is 47.

The spelling of 50543421446333 in words is "fifty trillion, five hundred forty-three billion, four hundred twenty-one million, four hundred forty-six thousand, three hundred thirty-three".