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5054405334073 is a prime number
BaseRepresentation
bin100100110001101001000…
…0010001101010000111001
3122220012022012100110022021
41021203102002031100321
51130302410231142243
614425543423354441
71031111606320354
oct111432202152071
918805265313267
105054405334073
11167961a052277
126976b2152a21
132a8822713b34
141368c51bd29b
158b723c056ed
hex498d208d439

5054405334073 has 2 divisors, whose sum is σ = 5054405334074. Its totient is φ = 5054405334072.

The previous prime is 5054405334031. The next prime is 5054405334079. The reversal of 5054405334073 is 3704335044505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4808336755264 + 246068578809 = 2192792^2 + 496053^2 .

It is a cyclic number.

It is not a de Polignac number, because 5054405334073 - 221 = 5054403236921 is a prime.

It is a super-2 number, since 2×50544053340732 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5054405334079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527202667036 + 2527202667037.

It is an arithmetic number, because the mean of its divisors is an integer number (2527202667037).

Almost surely, 25054405334073 is an apocalyptic number.

It is an amenable number.

5054405334073 is a deficient number, since it is larger than the sum of its proper divisors (1).

5054405334073 is an equidigital number, since it uses as much as digits as its factorization.

5054405334073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512000, while the sum is 43.

The spelling of 5054405334073 in words is "five trillion, fifty-four billion, four hundred five million, three hundred thirty-four thousand, seventy-three".