Base | Representation |
---|---|
bin | 10110111111000001111110… |
… | …01000000010111100010110 |
3 | 20121221222111120211211100211 |
4 | 23133200333020002330112 |
5 | 23111104042424310032 |
6 | 255255411201200034 |
7 | 13434462146046145 |
oct | 1337407710027426 |
9 | 217858446754324 |
10 | 50544234213142 |
11 | 1511776458962a |
12 | 580398993001a |
13 | 22283bac1a867 |
14 | c6a4d54b975c |
15 | 5c9b88d66747 |
hex | 2df83f202f16 |
50544234213142 has 4 divisors (see below), whose sum is σ = 75816351319716. Its totient is φ = 25272117106570.
The previous prime is 50544234213001. The next prime is 50544234213181. The reversal of 50544234213142 is 24131243244505.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×505442342131422 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50544234213095 and 50544234213104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12636058553284 + ... + 12636058553287.
It is an arithmetic number, because the mean of its divisors is an integer number (18954087829929).
Almost surely, 250544234213142 is an apocalyptic number.
50544234213142 is a deficient number, since it is larger than the sum of its proper divisors (25272117106574).
50544234213142 is a wasteful number, since it uses less digits than its factorization.
50544234213142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25272117106573.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 50544234213142 its reverse (24131243244505), we get a palindrome (74675477457647).
The spelling of 50544234213142 in words is "fifty trillion, five hundred forty-four billion, two hundred thirty-four million, two hundred thirteen thousand, one hundred forty-two".
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