Base | Representation |
---|---|
bin | 100100110010000111101… |
… | …1011000000000111111111 |
3 | 122220021221222022022011112 |
4 | 1021210033123000013333 |
5 | 1130312012410302111 |
6 | 14430233534112235 |
7 | 1031146253363324 |
oct | 111441733000777 |
9 | 18807858268145 |
10 | 5055435244031 |
11 | 1679aa8444927 |
12 | 69793b04b67b |
13 | 2a8957bc4003 |
14 | 136981cb4b4b |
15 | 8b784343e8b |
hex | 4990f6c01ff |
5055435244031 has 2 divisors, whose sum is σ = 5055435244032. Its totient is φ = 5055435244030.
The previous prime is 5055435244009. The next prime is 5055435244063. The reversal of 5055435244031 is 1304425345505.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5055435244031 - 222 = 5055431049727 is a prime.
It is a super-2 number, since 2×50554352440312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5055435244031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5055435244081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527717622015 + 2527717622016.
It is an arithmetic number, because the mean of its divisors is an integer number (2527717622016).
Almost surely, 25055435244031 is an apocalyptic number.
5055435244031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5055435244031 is an equidigital number, since it uses as much as digits as its factorization.
5055435244031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720000, while the sum is 41.
The spelling of 5055435244031 in words is "five trillion, fifty-five billion, four hundred thirty-five million, two hundred forty-four thousand, thirty-one".
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