Base | Representation |
---|---|
bin | 1001011010101010… |
… | …10100010111100111 |
3 | 111001022212120001022 |
4 | 10231111110113213 |
5 | 40323203433341 |
6 | 2153353321355 |
7 | 236165204615 |
oct | 45525242747 |
9 | 14038776038 |
10 | 5055530471 |
11 | 2164795962 |
12 | b9110625b |
13 | 627502364 |
14 | 35d5d86b5 |
15 | 1e8c74e4b |
hex | 12d5545e7 |
5055530471 has 2 divisors, whose sum is σ = 5055530472. Its totient is φ = 5055530470.
The previous prime is 5055530453. The next prime is 5055530527. The reversal of 5055530471 is 1740355505.
5055530471 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5055530471 - 26 = 5055530407 is a prime.
It is a super-3 number, since 3×50555304713 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5055530411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2527765235 + 2527765236.
It is an arithmetic number, because the mean of its divisors is an integer number (2527765236).
Almost surely, 25055530471 is an apocalyptic number.
5055530471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5055530471 is an equidigital number, since it uses as much as digits as its factorization.
5055530471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52500, while the sum is 35.
The square root of 5055530471 is about 71102.2536281376. The cubic root of 5055530471 is about 1716.2830395768.
Adding to 5055530471 its reverse (1740355505), we get a palindrome (6795885976).
The spelling of 5055530471 in words is "five billion, fifty-five million, five hundred thirty thousand, four hundred seventy-one".
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