Base | Representation |
---|---|
bin | 100100110100011101110… |
… | …0101010100111001000111 |
3 | 122220202221221012001220112 |
4 | 1021220323211110321013 |
5 | 1130402321101142320 |
6 | 14432425350223235 |
7 | 1031415122522006 |
oct | 111507345247107 |
9 | 18822857161815 |
10 | 5060471115335 |
11 | 1681152022539 |
12 | 698905654b1b |
13 | 2a927b30210c |
14 | 136cdca32c3d |
15 | 8b97b4d3ec5 |
hex | 49a3b954e47 |
5060471115335 has 32 divisors (see below), whose sum is σ = 6149490114240. Its totient is φ = 3997227520000.
The previous prime is 5060471115191. The next prime is 5060471115373. The reversal of 5060471115335 is 5335111740605.
It is not a de Polignac number, because 5060471115335 - 212 = 5060471111239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5060471115292 and 5060471115301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1556587460 + ... + 1556590710.
It is an arithmetic number, because the mean of its divisors is an integer number (192171566070).
Almost surely, 25060471115335 is an apocalyptic number.
5060471115335 is a deficient number, since it is larger than the sum of its proper divisors (1089018998905).
5060471115335 is a wasteful number, since it uses less digits than its factorization.
5060471115335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7219.
The product of its (nonzero) digits is 189000, while the sum is 41.
The spelling of 5060471115335 in words is "five trillion, sixty billion, four hundred seventy-one million, one hundred fifteen thousand, three hundred thirty-five".
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