Base | Representation |
---|---|
bin | 101111001001111010… |
… | …100011111111010001 |
3 | 11211200122102220001011 |
4 | 233021322203333101 |
5 | 1312143321244213 |
6 | 35132104010521 |
7 | 3441466463455 |
oct | 571172437721 |
9 | 154618386034 |
10 | 50632212433 |
11 | 1a522622670 |
12 | 9990760a41 |
13 | 4a0ba3661a |
14 | 26446a0665 |
15 | 14b512703d |
hex | bc9ea3fd1 |
50632212433 has 4 divisors (see below), whose sum is σ = 55235140848. Its totient is φ = 46029284020.
The previous prime is 50632212431. The next prime is 50632212457. The reversal of 50632212433 is 33421223605.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 50632212433 - 21 = 50632212431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 50632212395 and 50632212404.
It is not an unprimeable number, because it can be changed into a prime (50632212431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2301464191 + ... + 2301464212.
It is an arithmetic number, because the mean of its divisors is an integer number (13808785212).
Almost surely, 250632212433 is an apocalyptic number.
It is an amenable number.
50632212433 is a deficient number, since it is larger than the sum of its proper divisors (4602928415).
50632212433 is a wasteful number, since it uses less digits than its factorization.
50632212433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4602928414.
The product of its (nonzero) digits is 25920, while the sum is 31.
The spelling of 50632212433 in words is "fifty billion, six hundred thirty-two million, two hundred twelve thousand, four hundred thirty-three".
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