Base | Representation |
---|---|
bin | 100100110110111000001… |
… | …1101000011011110001011 |
3 | 122221021100002000111111212 |
4 | 1021231300131003132023 |
5 | 1130443424143402241 |
6 | 14435043502243335 |
7 | 1031660414650121 |
oct | 111556035033613 |
9 | 18837302014455 |
10 | 5065653106571 |
11 | 1683371132222 |
12 | 699910b8654b |
13 | 2a98c5a81015 |
14 | 137270d49911 |
15 | 8bb813d8beb |
hex | 49b7074378b |
5065653106571 has 2 divisors, whose sum is σ = 5065653106572. Its totient is φ = 5065653106570.
The previous prime is 5065653106439. The next prime is 5065653106573. The reversal of 5065653106571 is 1756013565605.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5065653106571 is a prime.
It is a super-3 number, since 3×50656531065713 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 5065653106573, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (5065653106573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2532826553285 + 2532826553286.
It is an arithmetic number, because the mean of its divisors is an integer number (2532826553286).
Almost surely, 25065653106571 is an apocalyptic number.
5065653106571 is a deficient number, since it is larger than the sum of its proper divisors (1).
5065653106571 is an equidigital number, since it uses as much as digits as its factorization.
5065653106571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2835000, while the sum is 50.
The spelling of 5065653106571 in words is "five trillion, sixty-five billion, six hundred fifty-three million, one hundred six thousand, five hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •