Base | Representation |
---|---|
bin | 101111001011101000… |
… | …011010111010101001 |
3 | 11211202122122000101221 |
4 | 233023220122322221 |
5 | 1312223204323423 |
6 | 35135013142041 |
7 | 3442266326566 |
oct | 571350327251 |
9 | 154678560357 |
10 | 50661011113 |
11 | 1a537902529 |
12 | 999a32a921 |
13 | 4a149aa86b |
14 | 264843986d |
15 | 14b7914e5d |
hex | bcba1aea9 |
50661011113 has 2 divisors, whose sum is σ = 50661011114. Its totient is φ = 50661011112.
The previous prime is 50661011101. The next prime is 50661011153. The reversal of 50661011113 is 31111016605.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 50513461504 + 147549609 = 224752^2 + 12147^2 .
It is a cyclic number.
It is not a de Polignac number, because 50661011113 - 25 = 50661011081 is a prime.
It is not a weakly prime, because it can be changed into another prime (50661011153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25330505556 + 25330505557.
It is an arithmetic number, because the mean of its divisors is an integer number (25330505557).
Almost surely, 250661011113 is an apocalyptic number.
It is an amenable number.
50661011113 is a deficient number, since it is larger than the sum of its proper divisors (1).
50661011113 is an equidigital number, since it uses as much as digits as its factorization.
50661011113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 25.
Adding to 50661011113 its reverse (31111016605), we get a palindrome (81772027718).
The spelling of 50661011113 in words is "fifty billion, six hundred sixty-one million, eleven thousand, one hundred thirteen".
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